two line segments AC and BD bisect each other at O prove that ABCD is a parallelogram
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solution⤵️
Given,
two line segments AC and BD bisect each other at O
=>OA=OC and OB=OD
To prove: ABCD is a parallelogram
construction:AB,BC,CD and DA are joined
proof: in ∆AOB and ∆COD
OA=OC (given)
OB=OD (given)
<AOB=<COD (Vertically opposite angles)
therefore,∆AOB=~∆COD (SAS)
=> <OAB=<COD (CPCT)
=> AB||CD➡️[1]
also AB=CD➡️[2]
from[1] & [2],
ABCD is a parallelogram
hence proved
Given,
two line segments AC and BD bisect each other at O
=>OA=OC and OB=OD
To prove: ABCD is a parallelogram
construction:AB,BC,CD and DA are joined
proof: in ∆AOB and ∆COD
OA=OC (given)
OB=OD (given)
<AOB=<COD (Vertically opposite angles)
therefore,∆AOB=~∆COD (SAS)
=> <OAB=<COD (CPCT)
=> AB||CD➡️[1]
also AB=CD➡️[2]
from[1] & [2],
ABCD is a parallelogram
hence proved
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Answer:
To Prove= ABCD is a parallelogram
PROOF =in traingle AOB and COD
AO=CO
BO=DO
Angle AOB=Angle COD
so proof it is congurent
so angle 1=angle =2 hence parallel it is a quadrilateral and a parallelogram
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