Two lines AB and CD intersect at a point O such that ∠BOC + ∠AOD = 280°, as shown in the given figure. Find all the four angles.
mhmohshin:
do you need the figure
with out figure cant you find the answer
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Answered by
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Angle BOC = Angle AOD (V.O.A)
then we take ANGLE BOC = 140°
So, Angle AOD = 140°
NOW, LINE OD STAND ON AC SO THEY MAKE LINEAR PAIR
NOW, ANGLE AOD + ANGLE COD =180°
SO, 140° + ANGLE COD = 180°
ANGLE COD =40°
ANGLE COD = ANGLE BOA
ANGLE BOA = 40°
NOW, FOUR ANGLE ARE 140°, 40°, 140°, 40°
then we take ANGLE BOC = 140°
So, Angle AOD = 140°
NOW, LINE OD STAND ON AC SO THEY MAKE LINEAR PAIR
NOW, ANGLE AOD + ANGLE COD =180°
SO, 140° + ANGLE COD = 180°
ANGLE COD =40°
ANGLE COD = ANGLE BOA
ANGLE BOA = 40°
NOW, FOUR ANGLE ARE 140°, 40°, 140°, 40°
thanks for you answer
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