Question

two lines ad and bc intersect at o . a and b are joined c and d are jpined angle b = angle c = angle d = angle a prove ad = bc​

Answer 1

Answer:

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Step-by-step explanation:

Since, the bisectors of a triangle are concurrent, then AY is the bisector of ∠A.

Then from angle-bisector property we get, [Using the bisector of ∠C ]

XYAX=YCAC........(1).

Again, since AY is the bisector of ∠A then 

YCBY=ACAB

or, YCBY=45

or, YCBY+YC=45+4

or, YCBC=49

or, YC=38.

From (1) we get, 

XYAX=23.

Answer 2

things should know before

doing the sum

they are

if base angles are equal then adjacent sides are also equal.

and the lines which are parallel and the intersecting lines makes equal angles with the both bases then the length of both parallel lines are equal and also the length of the lines are equal

now coming to the sum

<A =<D

<C=<B

<AOB = <DOB

so by using

AAA axiom

∆AOB ≈ ∆DOC

means both the triangles are concernt

so

AO = CO=BO=DO

so

AO+OD=OC+OB

AD=BC