Question

Two lines are given to be parallel the equation of one of the line is 4x +3y =14, then find the equation of secondline

Answer 1

Explanation:

This is the answer to the question. Ask me another question in 10th std topic

Answer 2

There can be many such equations like

8x+6y = 15

EXPLANATION:-

Given-

• Two lines are parallel.
• Equation of one line ---> 4x+3y = 14.

To find-

• The equation of second line.

As we know that parallel lines has no common solution.

And for no solution,

$a \frac{}{1} \div a \frac{}{2} = b \frac{}{1} \div b \frac{}{2} \\ not \: equal \: to \:c \frac{}{1} \div c \frac{}{2}$

Where a and b are the coefficient of x, y respectively, and c is the constant term.

Therefore in order to be a parallel line the equation should satisfy the above condition.

Let the coefficient of x², x and the constant term of the second equation be a,b and c respectively.

So the line will be parallel if,

$4 \div a = 3 \div b \: \\ not\: equal \: to \:14 \div c$

$4 \div </em></strong><strong><em>8</em></strong><strong><em> = 3 \div </em></strong><strong><em>6</em></strong><strong><em> \: \\ not\: equal \: to \:14 \div </em></strong><strong><em>5</em></strong><strong><em>$

So the required value of a, b and c is 8, 6 and 5

{since 4÷8=1/2, 3÷6=1/2}

Therefore the equation will be-

8x+6y = 5

{Note that there can be many such equations which can satisfy the condition}