Question

Two lines are given to be parallel. The equation of one of the lines is 4x + 3y = 14, then find the
quation of a second line.​

Answer 1

Step-by-step explanation:

This was told by my big bro

For parallel lines condition is

A1/A2 = B1/B2 = C1/C2

4x+3y=14-----equation 1

8x+6y=7------equation 2

1/2=1/2

LHS=RHS

or

This is mine

Equation of a line ax+by+c=0

Parallel to given line is ax+by+k=0

Here k is any real number

Therefore, Required parallel line is 4x+3y=k

Example:

4x+3y=5

4x+3y=-7