Question

Two lines are given to be parallel.
The equation of one of the lines is
4x + 3y = 14, then the equation of
the second line is​

Answer 1

Answer:

Equation of a line ax + by + c = 0 parallel to given line is ax + by + k = 0 here k is any real number. Therefore , Required parallel line is 4x + 3y = k Example : 4x + 3y = 5 , 4x + 3y = - 7Read more on Sarthaks.com - https://www.sarthaks.com/838092/lines-given-parallel-the-equation-one-the-equation-then-find-the-equation-the-second-line

Step-by-step explanation:

Equation of a line ax + by + c = 0 parallel to given line is ax + by + k = 0 here k is any real number. Therefore , Required parallel line is 4x + 3y = k Example : 4x + 3y = 5 , 4x + 3y = - 7Read more on Sarthaks.com - https://www.sarthaks.com/838092/lines-given-parallel-the-equation-one-the-equation-then-find-the-equation-the-second-line

Answer 2

Answer:

angle of parallel line =180•

so let tge given equation is ,

4x =180

x = 25

3y =180

y = 6

4*25 + 3*6 = 14