Two lines cut the axis of x, at distances of 4 and - 4 and the axis of y at distances 2 and
6 respectively. Find the co-ordinates of their point of intersection.
harinderyadavy27:
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Solution
If two point of line is given then equation
of line is = (y-yı) = 42-4, (X-XI)
y wing tw's formula , we get
. eg of 1 line 3) (9-0) = 2-0 (x-4) 0-4
=> y = (x-4)
amd vega 8 200 line =) (y-o) = 6-6 0-(-4) (2+4)
-> y = (x+4)
By solving both eq ; we get intersection point + 2y = -x+4 3) x+2y = 4
28 = 3x+12 7)-3x +2y =12 2
Subtracting egr 0 and , we get
;3* y = 12
4x = 8
x = -2
put value of x in
- 2+2y = 4 2y=6
y=37
So, the point o intersection (-2,3)
CSScann n SscopHm (B) is correct.
Step-by-step explanation:
I hope it is helpful to you
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