Two lines l and m intersect at a point O. If anglex = 100°, the measure of angles angle 1, angle 2 and angle three
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Lines, l and m and n intersect at point O,P is a point on line n and such that P is equidistant from l and n.
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To prove: n us the bisector of ∠QOR
Proof: In ΔOQP and ΔORP, we have
∠1=∠2
[∵ Each equal to 90° ]
OP=OP [Common side]
PQ=QR [Given]
So, by RHS criterion of congruence, we have
ΔOQP≅ΔORP
∴∠3=∠4 [CPCT]
So, n is bisector of ∠QOR
Hence, proved.
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