Two lines x-1/2=y+1/3=z-1/4 and x-3/1=y-k/2=z intersect at point then 2k=
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12 @@+88276hwbb. ebehdi rudro finding emi so ekdin
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L1=x−12=y+12=z−14 ; passes from (1,-1,1)
L2=x−31=y−k2=z1 ; passes from (3,k,0)
L1&L2 are in same plane
Dr'sofL1=(2,2,4)
Dr'sofL2=(1,2,1)
line L3 passes from (1,-1,1) & (3, k ,0)
Dr'sofL3=(2,k+1,−1)
L1,L2,L3are coplanar
[L1L2L3]=0=∣∣∣∣21232k+141−1∣∣∣∣=0
=2(−2−k−1)−3(−1−2)+4(k+1−4)=0
−6−2k+9+4k−12=0
2k−9=0
k=92
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