Question

two liquid X and Y mixed in 3:2 growth of liquid X is 2 Rs per little more than y . worth of final mixture 10 Rs per litre . find the worth of liquid x?​

Answer 1

Answer:

I know what is the answer

Answer 2

Answer:

Let Cost of X be x

Cost of Y be y

and their volumes be 3K and 2K

Now, x=y+2

Let original price be P

So, P+10% of P=11

P+0.1P=11

1.1P=11

P=10

So,

3K+2K

3Kx+2Ky

=

5

3x+2y

=10

3x+2y=50....(1)

and x=y+2....(2)

Using (2) in (1), we get

⇒3y+6+2y=50⇒5y=44⇒y=

5

44

=8.8 Rs.

Step-by-step explanation:

sorry if my and is wrong