two liquid X and Y mixed in 3:2 growth of liquid X is 2 Rs per little more than y . worth of final mixture 10 Rs per litre . find the worth of liquid x
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Answer:
worth of x = rs 10.8
Step-by-step explanation:
as given, the new liquid will have liquid x and y in the ratio of 3:2
and, let the worth of liquid (y) = rs p
then according to the question,
worth of x = rs '(2+p)'
now.
the new liquid can be obtained by taking 3 litres of x and 2 litres of y according to the question. (as the ratio of x and y is 3:2)
worth of 5 litres of new liquid = (worth of 3 litres of x) + (worth of 2 litres of y)
rs 50 = 3*(2+p) + 2*p
rs 50 = 6+5p
5p = rs 44
p = rs 8.8 (which is the cost of the liquid y)
cost of liquid x = (2+p) = rs 10.8
hence, rs 10.8 is the required value of liquid x.
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