Two liquids A and B are at 32o C and 24o C. When mixed in equal masses the temperature of the mixture is found
to be 28o C. Their sp. heats
are in the ratio of
(A) 3 : 2 (B) 2 : 3
(C) 1 : 1 (D) 4 : 3
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1
Answer:
Answer is 1:1
Explanation:
temperature of mixture Φmix = ΦA cA + ΦB cB/cA+cB
=> 28= 32×cA+24×cB/cA+cB
=> 29 cA+ 28 cB=32cA+24cB
=> cA/cB=1/1
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