Physics, asked by ReddyRachana, 10 months ago

Two liquids A and B are at temperature of 75°C
and 150°C respectively. Their masses are in the
ratio of 2 : 3 and specific heats are in the ratio 3:
4. The resultant temperature of the mixture,
when the above liquids, are mixed (Neglect the
water equivalent of container) is
125°C
100°C
50°C
150°C​

Answers

Answered by Anonymous
2

Answer: A

Solution :

mASA(θ−75)=mBSB(150−θ).

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