Question

Two liquids A and B are in the ratio 5 : 1 in cotainer and 1 : 3 in container 2. In what ratio should the contents be mixed so as to obtain a mixture of A and B in the ratio 1 : 1 ?​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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Ler each side of the triangle be a cm.

Area of triangle ABC = Area of triangle AOB + Area of triangle AOC + Area of triangle BOC

$= > \frac{ \sqrt{3} }{4} a {}^{2} = \frac{1}{2} \times a \times \sqrt{3} + \frac{1}{2} \times a \times 2 \sqrt{3} + \frac{1}{2} \times a \times 5 \sqrt{3}$

$= > \frac{ \sqrt{3} }{4} a {}^{2} = \frac{1}{2} a( \sqrt{3} + 2 \sqrt{3} + 5 \sqrt{3} )$

$= > \frac{ \sqrt{3} }{4}a {}^{2} = \frac{1}{2} \times a \times 8 \sqrt{3} \\ = > \frac{ \sqrt{3} }{4} a = \frac{1}{2} \times 8 \sqrt{3}$

$= > a = \frac{8 \sqrt{3} }{2} \times \frac{4}{ \sqrt{3} } \\ = > a = 16$

Therefore, perimeter of the triangle

= 16 × 3 = 48 cm.