Math, asked by gaanabajana92, 6 months ago

Two liquids A and B are in the ratio 5 : 1 in cotainer and 1 : 3 in container 2. In what ratio should the contents be mixed so as to obtain a mixture of A and B in the ratio 1 : 1 ?​

Answers

Answered by Anonymous
1

Answer:

\huge\underline\bold {Answer:}

Let the required be x : y

Liquid A in x litres of mixture in container 1

= 5x/6 litres

Liquid B in x litres of mixture in container 1

= x/6 litres

Liquid A in y litres of mixture in container 2

= y/4 litres

Liquid B in y litres of mixture in container 2

= 3y/4 litres

Therefore Liquid A : Liquid B

 = ( \frac{5x}{6}  +  \frac{y}{4} ) \div ( \frac{x}{6}  +  \frac{3y}{4} )

Given,

 \frac{( \frac{5x}{6} +  \frac{y}{4} ) }{( \frac{x}{6}  +  \frac{3y}{4} )}  =  \frac{1}{1}

=> 5x/6 + y/4 = x/6 + 3y/4

=> 5x - x/6 = 3y/4 - y/4

=> 4x/6 = 2y/4

=> 2x/3 = y/2

=> x/y = 3/4.

Therefore in 3/4 ratio the contents of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1 : 1

Similar questions