Chemistry, asked by divyanshgupta28, 11 months ago

Two liquids A and B from ideal solution at 323 K. A liquid mixture
containing one mole of A and two mole of B has a vapour pressure of 250
m bar. If one more mole of A is added to the solution, the vapour pressure
ncrease to 300 m bar. Calculate the vapour pressures of liquids A and B at 323K​

Answers

Answered by Anonymous
3

calculate the mass of 1 dm3 of NH3 gas at 30°c 1000mmhg pressure considering tha NH3 behave ideally?

V1 = 302 ml

P1 = 0.52 atm

P2 = ?

V2 = 69 ml Boyle's Law P1V1 = P2V2

P2 = P1V1/V2 P2 =

(0.52 atm)(302 ml)/69 ml

P2 = 2.3 atm...

Similar questions