Two liquids a and b from ideal solution,at 333k ,the vapour pressure of a solution containing a and b in 1:2 molar ratiois 300 torr and of a slotion containing equal number of moles of a and b is 350torr.What are the vapour pressure of pure a and b at 333k?
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Since P=xAP0A+xBP0B
⇒(11+3)P0A+(31+3)P∘B=550mm Hg
⇒(11+4)P0A+(41+4)P∘B=560mm Hg
That is,
0.25P0A+0.75P0B=550mm Hg
0.20P0A+0.8P0B=560mm Hg
Solving for P0A and P0B we get,
P0A=400 mm Hg
P0B=600 mm Hg
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