Question

two liquids of different densities (p1=1500 kg/cu.m., p2 = 500kg/cu.m.) are poured together into a 100 L tank, filling it. if the resulting density of the mixture is 800 kg/cu.m, find the respective quantities of liquids used.

Answer 1

Answer:

I think it is help full to you

Explanation:

I would be inclined to change the kg/m&3 to g/cc and change 100 L to cc but you aren't required to do that if you want to stay in the units and change 100 L to cubic meters.

So 1500 kg/m^3 = 1.5 g/cc

500 kg/m^3 = 0.500 g/cc

100L = 100,000 cc.

How much does the 100 L tank weigh?

100 x 0.800 g/cc = 80,000g

Let x = mass 1500 stuff.

Then 100,000-x = mass 500 stuff.

1.5g/cc * x + 0.500g/cc *(100,000-x) = 80,000 and solve for x and 100,000-x.

Answer 2

Given: Two liquids of different densities are poured together into a 100 L tank, filling it and the resulting density of the mixture is 800 kg/cubic metre.

To find: The respective quantities of liquids used.

Solution:

• Density is the amount of substance, in this case, liquis, present per cubic metre.
• It is given by the formula,

       $d = \frac{m}{V}$

• Here, d is the density of the liquid, m is the mass or the quantity and V is the volume.

• Let the quantity of the first liquid poured be equal to x and let the quantity of the second liquid poured be equal to (100L -x).
• So, to find the quantities of the liquid, we use the following equation,

        $(1500kg/cu.m * x) + (500kg/cu.m * (100-x)) = 800 kg/cu.m$

        $1500x + 50000 - 500x = 800$

         $x = 49.2 kg$

• To find the mass of the other liquid,

        $100-49.2 = 50.8kg$

Therefore, the respective quantities of liquids used is 49.2 kg and 50.8 kg.