Chemistry, asked by Chinmayi20021, 9 months ago

Two liquids X and Y on mixing from an ideal solution. The vapour pressure of

the solution containing 2 mol of X and 1 mol of Y is 550 mm Hg. But when 4 mol

of X and 1 mole of Y are mixed, the vapour pressure of solution thus formed is 560

mm Hg. What will be the vapour pressure of pure X and pure Y at this temperature?

Answers

Answered by Sumitnegi58

Answer:

ANSWER

ANSWERLet

ANSWERLet P=x

ANSWERLet P=x x

ANSWERLet P=x x P

ANSWERLet P=x x P x

ANSWERLet P=x x P x0

ANSWERLet P=x x P x0 +x

ANSWERLet P=x x P x0 +x y

ANSWERLet P=x x P x0 +x y P

ANSWERLet P=x x P x0 +x y P y

ANSWERLet P=x x P x0 +x y P y0

ANSWERLet P=x x P x0 +x y P y0 (

ANSWERLet P=x x P x0 +x y P y0 ( 1+3

ANSWERLet P=x x P x0 +x y P y0 ( 1+31

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +(

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+3

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg(

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+4

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +(

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+4

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHg

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P y

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P y0

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P y0 and P

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P y0 and P x

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P y0 and P x0

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P y0 and P x0We get,

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P y0 and P x0We get,P

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P y0 and P x0We get,P x

ANSWERLet P=x x P x0 +x y P y0 ( 1+31 )P x0 +( 1+33 )P y0 =550mmofHg( 1+41 )P x0 +( 1+44 )P y0 =560mmofHgon solving for P y0 and P x0We get,P x0

=400mmofHg

=400mmofHgP

=400mmofHgP y

=400mmofHgP y0

=400mmofHgP y0 =600mmofHg

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