Question

Two litre glass flask contains some mercury. It is found that at all temperatures the volume of the air inside the flask remains the same. The volume of the
mercury inside the flask is (a for glass = 9 x 10-6/°C. y for mercury = 1.8 x 10-4/°C)
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Answer 1

Explanation:

Given Two litre glass flask contains some mercury. It is found that at all temperatures the volume of the air inside the flask remains the same. The volume of the mercury inside the flask is (a for glass = 9 x 10-6/°C. y for mercury = 1.8 x 10-4/°C)

• Given the volume of the air inside the flask remains same.
• Both the expansion of mercury and the container are same.
• We need to find the volume of mercury.
• Now final volume will be v1 = v (1 + γ ΔT)
• Now change in volume of liquid Δv = v1 – v
•                                                             = vγΔT
• So change in volume of mercury = change in volume of flask.
• So we have       (vγΔT) mercury = (vγΔT) flask
•    So v x 1.8 x 10^-4 ΔT = 2000 x γ x ΔT (1 litre = 1 dm^3 or 10 cm = 1000 cm^3)
•    So 1.8 x 10^-4 ΔT = 2000 x 3 x  9 x 10^-6 x ΔT  (γ = 3α)
•       Now v = 2000 x 27 x 10^-6 / 1.8 x 10^-4
•                    = 2000 x 15 x 10^-2
•                      = 300 cm^3        

Reference link will be

https://brainly.in/question/2256538