Two litres of a mixture of wine and water contains 12% water. they are added to 3 litres of another mixture containing 7% water, and half a litre of water is the added to whole. what is the percentage of water in resulting concoction?
Answers
The percentage of water in resulting concoction is 17.59%:
Step-by-step explanation:
2 liter of mixture contains 12% water and 88% alcohol.
Amount of water in L = 12/ 100 x 2 = 6 / 25 L
Amount of alcohol in L = 88/100 x 2 = 44/25 L
Now the concentration of each solute in 3 L mixture.
3 liter of mixture contains 7% water and 93% alcohol.
Amount of water in L = 7/ 100 x 3 = 21 / 100 L
Amount of alcohol in L = 93 / 100 x 3 = 279 /100 L
By mixing them we get.
[21 / 100 + 6 /25] L water = [279 /100 + 44/25] L Alcohol
45 / 100 L water = 455 / 100 L Alcohol
Now we will add 1/2 liter of water =[ 45 / 100 + 1/2 ]
= 95 / 100 L
Total volume of water = [95 / 100 L] + [ 455 / 100 L] = 540 / 100
= 5.4 L
The percentage of water in resulting concoction = 0.95 x 100 / 5.4 %
= 17.59%
Hence the percentage of water in resulting concoction is 17.59%
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