two long parallel conductor carry 100A current if the conductor are separated by 20mm the force per meter of length of each conductor will be
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Given data: Current I1 and I2 = 100 Amps; Distance = 20 mm = 20 10-3 m; Force = ? We know that the force is found by the following expression. Torque developed force fT=M0 *I1 *I2/(2*(Pi)*d)=4*(Pi)*(10)^-7 *(100)^2/2*(pi)*20*(10)^-3=0.1 N
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