Question

two magnetic poles one of which is four times stronger than other exert a force of 5gf on each other when placed at a dist of 10cm find strength of each pole​

Answer 1

hope this helps you☺️☺️☺️

Answer 2

Here's ur answer mate!!

◆ Answer -

m1 = 5 A.m

m2 = 20 A.m

● Explaination -

# Given -

F = 1 mN = 10^-3 N

r = 0.1 m

m2 = 4m1

# Solution -

According to Coulomb's law -

F = (μ/4π) m1.m2/r^2

10^-3 = 10^-7 × m1.m2 / 0.1^2

m1.m2 = 10^-3 × 10^-2 / 10^-7

m1.m2 = 100

Given that m2 = 4m1,

m1 × 4m1 = 100

m1^2 = 100/4

m1^2 = 25

m1 = 5 A.m

Now,

m2 = 4m1

m2 = 4×5

m2 = 20 A.m

Therefore, strength of one pole is 5 Am and other pole is 20 Am.

Hope this helps you...