Math, asked by groversimran1996, 2 months ago

Two man can do a piece of work in 6 hours and 4 hours respectively. After the first has worked for 2 hours, he is joined by other. By when should work be completed.​

Answers

Answered by IIRythvikII
250

⭐REQUIRED ANSWER⭐

3 Hours and 36 minutes ✔

STEP BY STEP EXPLANATION⤵️

Let the two men be A and B.

GIVEN,

A can do a piece of work in 6 hours 13 in 4 hours.

A's 1 hour work = 1/6

B's 1 hour work = 1/4

Both (A+B)'s 1 hour work = 1/6 + 1/4 = 5/12

After the 1st has worked for 2 hours, he joined the other

A's two hour work = 2 × 1/6 = 1/3

Remaining work = 1 - 1/3 = 2/3

5/12 work is done by (A+B) in 1 hour

2/3 work is done by (A+B) in 12/5 × 2/3 = 8/5 hours

TOTAL TIME TAKEN TO COMPLETE THE WORK = 2 + 8/5

= 18/5

= 3 3/5 hours

= 3 hours and 36 minutes

Answered by vaishnavi9290
4

Two men, say A and B, can do a piece of work in 6 hours and 4 hours, respectively. After the first,A, has worked for 2 hours, he is joined by the other, B. When should the work be completed?

If A can do the work in 6 hours , he does 1/6th of the work in an hour and in 2 hours he would have done 1/3rd of the work. What remains to be done is 2/3rd.

If B can do the work in 4 hours, he does 1/4th of the work in an hour. A and B together do (1/6)+(1/4) = (2/12)+(3/12) = 5/12th part of the work in an hour.

To complete the remaining 2/3rd of the work A and B will need to work for (2/3)/(5/12) or 2*12/(3*5) or 8/5 hours or 1.6 hours.

Hence the total duration worked, from the beginning, by A and B is 2+1.6 = 3.6 hours.

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