Two man can do a piece of work in 6 hours and 4 hours respictively after the first can work for 2 hour he is join by the other
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firstly we have to calculate their efficiency so can be easily solved.
now let A and B two person so
A =6hours
B= 4hours.
so LCM = 12 so we have to assume work is 12 unit.
now their efficiency = A= 12/6=2
B= 12 /4=3
now given -- first 2hour only a so 2e×2h=4w
last 8 work will be done by both so 8w/5e= 1.6 or 1 hour and 36 minutes.
so total time = 3 hours and 36 minutes.
now let A and B two person so
A =6hours
B= 4hours.
so LCM = 12 so we have to assume work is 12 unit.
now their efficiency = A= 12/6=2
B= 12 /4=3
now given -- first 2hour only a so 2e×2h=4w
last 8 work will be done by both so 8w/5e= 1.6 or 1 hour and 36 minutes.
so total time = 3 hours and 36 minutes.
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