Question

Two mass each of 60g are attached to a friction less pulley when 10g mass is added to one of the mass what is its downward acceleration

Answer 1

$\checkmark$ Answer

Formula:

$\boxed{\sf Force \ (F) = m \times g}$

Given,

Mass (m) added = 10 g

Taking g = 9.8 m/s² = 981 cm/s²

$\implies \sf F = 10 \times 981 = 9810$

Now,

The total mass being accelerated is

Mass (m) = 60 + 60 + 10 = 130 g

Since Given that,

Two blocks of mass 60 g

We know that,

Formula:

$\boxed{\sf Acceleration (a)=\dfrac{Force(F)}{Mass (M)} }$

So,

$\implies \sf a = \dfrac{9810}{130} \ cm/s^2$

$\sf \implies a=75.469 \ cm/s^2$