Two mass m and 2m are attached with each other by a rope
passing over a frictionless and massless pulley. If the pulley
is accelerated upwards with an acceleration ‘a’, what is the
value of T?
(a)g + a/3
(b)g - a/3
(c)4m(g + a)/3
(d)m(g - a)/3
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The force balance equation for 2m will be
2mg−T=2ma2mg−T=2ma
And for m, it will be
T−mg=maT−mg=ma
Solving for a, we get
{eq}a=\dfrac{...
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