Two masses 10 kg and 20 kg are connected by a massless spring. A force of 200 N acts on 20
kg mass. At the instant when the 10 kg mass has an acceleration 12 m/s, find the energy stored
(in Joule) in the spring (k = 2400 N/m).
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Answer:
m 1 = 10kg;m
2
=20kg;F
2
=200N;a
1
=12ms
−2
;a
2
=?
For mass m
1
; F=m
1
a
1
=10×12=120N
For mass m
2
;
200−F=20a
2
200−120=20a
2
a
2
=
20
80
=4ms
−2
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