two masses 10 kg and 6 kg is attached to free ends of a string passing over a pulley. when the bodies are released, the acceleration of the masses is
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When the bodies are released, the acceleration of the masses is 2.45m/s².
Let the tension in the string be T N
For the heavier mass 10kg, its weight is 10kgf.
Let acceleration of the mass be 'a' m/s²
Difference between Tension and Weight of the body = Mass×Acc.
So, 10g-T = 10a
⇒T = 10g - 10a ...(1)
where g is the acceleration due to gravity
For the lighter mass 6kg, its weight is 6kgf.
Difference between Tension and Weight of the body = Mass×Acc.
So, T-6g = 6a ...(2)
Substituting the value of T from (1) in (2),
10g-10a -6g = 6a
⇒4g = 16a
⇒a = g/4
where g = 9.8m/s²
So, a = 9.8/4 = 2.45m/s²
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