Question

two masses 100 kg and 250 kg keep apart distance of 3 into 10 ^ -5 what will be the gravitational force between them​

Answer 1

$\huge{\underline{\underline{\red{\mathfrak{AnSwEr :}}}}}$

$\small{\underline{\blue{\sf{Given :}}}}$

• Mass of First Body (m1) = 100kg

• Mass of Second Body (m2) = 250 kg

• Distance between them 3*10^(-5)

$\rule{200}{1}$

$\small{\underline{\green{\sf{Solution :}}}}$

We have formula :

$\large \star {\boxed{\sf{g \: = \: G \dfrac{ \big( m_1 \big) \big( m_2 \big )}{d^2}}}} \\ \\ \implies {\sf{g \: = \: G \dfrac{ \big( 100 \big) \big(250 \big)}{ \big( 3 \: \times \: 10^{-5} \big) ^2}}} \\ \\ \implies {\sf{g \: = \: \dfrac{ \big( 6.67 \: \times \: 10^{11} \big) \big(25000 \big)}{9 \: \times \: 10^{-10}}}} \\ \\ \implies {\sf{g \: = \: \dfrac{ \big( 6.67 \: \times \: 10^{14} \big) \big(25 \big) }{9 \: \times \: 10^{-10}}}} \\ \\ \implies {\sf{g \: = \: \dfrac{ \big( 6.67 \: \times \: 10^{23} \big) \big( 25 \big)}{9}}} \\ \\ \implies {\sf{g \: = \: 1.85 \: \times \: 10^{24}}} \\ \\ {\boxed{\sf{g \: = \: 1.85 \: \times \: 10^{24} \: N}}}$

∴ Gravitational Force Between Them Is 1.85 * 10^(24) N