Question

Two masses 10kg and 20kg are separated by distance r, find the position of centre
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Answer 1

Answer:The equation for this is F = -GmM/R^2 where the minus sign says the force is attractive m is 10 kg, M is 20 kg and R is 5 meters. If you crunch the numbers you get an answer of:

Where 1 Newton = 1 Kg m/sec^2

Explanation:

Answer 2

The position of center of mass is $\dfrac{2r}{3}$.

Explanation:

Given that,

Mass of the first object, $m_1=10\ kg$

Mass of the second object, $m_2=20\ kg$

They are separated by a distance of r. We can take our reference at position of 10 kg mass. Its position will be at (0,0). So, the center of mass of two objects is given by :

$m_{cm}=\dfrac{m_1r_1+m_2r_2}{m_1+m_2 }$

$m_{cm}=\dfrac{10(0)+20(r)}{10+20}$

$m_{cm}=\dfrac{20r}{30}$

$m_{cm}=\dfrac{2r}{3}$

So, the position of center of mass is $\dfrac{2r}{3}$. Hence, this is the required solution.

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