Question

two masses 1g and 4g are moving with equal kinetic energies. The ratio of the magnitudes of their monenta is?

Answer 1

$since \: they \: are \: moving \: with \: same \: kinetic \: energy \: therefore \: they \: will \: hav \: same \: velocities \\ \\ let \: their \: common \: velocities \: be \: v \: and \: let \: m_{a} = 1g = 0.001 \: and \: m_{b} = 4g = 0.004kg$
now momentum of first object:momentum of second object=ma×v:mb×v
=ma:mb
=1:4..... answer

Answer 2

kinetic energy = 1/2mv^2
Ist masses kinetic energy =2nd masses kinetic energy
1/2mv^2=1/2MV^2
1*v^2=4*V^2
V^2/v^2=1/4
V/v=1/2