Question

Two masses 2 gram and 8gram are moving with equal kinetic
energy in the ratio of linear
momentum

Answer 1

the ratio must be 1:1

Answer 2

K.E = $\frac{ P^{2}} {2m}$

K.E = $\frac{ P^{2} _{1}} {2m}_{1}$

p =  $\sqrt{(K.E)(2(2))}$

$P_{1}=  \sqrt{(K.E)(2(8))}$

$\frac{P}{P_{1}} =\sqrt{ \frac{4K.E}{16K.E}$}

$p:p_{1} = \sqrt{1:4}$

$p :p_{1} = 1:2$

Brainliest please