Question

Two masses 2kg and 3kg are attached to the end of the string passing over a pulley fixed at the top the tension and acceleration are

Answer 1

Answer:m1 = 2kg

m2= 3kg

Now,

T= (2m1 × m2 / m1 × m2 )g

= (2 ×2 ×3/ 2+3 )g

= 12/5 g

a = (m2 - m1 / m1+ m2) g

= (3-2/3+2)g

= g/5

Explanation: