Question

Two masses 48kg and 3kg are moving with equal kinetic energy calculate the ratio of magnitude of their linear momentum

Answer 1

Heya mate !! ❣️❣️

Answer...

$p \: = \: \sqrt{2mk}$

since kinetic energy is constant,

$\frac{p1}{p2} = \frac{ \sqrt{m1} }{ \sqrt{m2} } \\ \\ = \sqrt{ \frac{48}{3} } \\ \\ = \sqrt{16} \\ \\ = 4</em><em>:</em><em>1</em><em>$

hope helps !! ❤️❤️

Answer 2

P = linear momentum = mv = √(2mE)

{where E is Kinetic energy}

Since E is same for both ;

p is proportional to √m

Hence, ratio of p1/p2 = √(48/3) = √16 = 4:1