Question

two masses 4kg and 2 kg are connected to the ends of the light inextensible string which passes over the surface of smooth fixed Pulley if the system is released from rest the acceleration of the centre of mass of the system will be g=10 m/second square​

Answer 1

Answer:

Explanation:answer for this question is 10/9m/sec2

Answer 2

4kg is moving downward with an acceleration a and 2kg is moving upward with the same acceleration a.

now, a = (m2 - m1)/(m1 + m2) × g

= (4 - 2)/(4 + 2)g

= g/3

so, acceleration of mass 4kg, $a_1$ = -a = -g/3

acceleration of mass 2kg, $a_2$ = a = g/3

now, acceleration of centre of mass of the system = $\frac{m_1a_1+m_2a_2}{m_1+m_2}$

= (4kg × -g/3 + 2kg × g/3)/(4kg + 2kg)

= (-2g/3)/(6)

= -g/9

= -10/9 = -1.11 m/s²

hence, acceleration of centre of mass of the system is 1.11m/s² [ downward]