Question

Two masses 5 kg and 3kg are suspended with help of masses inextensible string telugu at t1 and t2 in our system is going upward with acceleration to metre per second square

Answer 1

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$\it\huge\mathfrak\red{Given:-}$]

M₁=5kg

T is acting upwards whereas m₁g is acting downwards.

m₁g>T .........(m₁>m₂)

Free body diagram of m₂=3kg

T is acting upwards whereas m₂g acts downwards.

$\it\huge\mathfrak\red{Solution:-}$]

m₂g<T

m₁g-T=m₁a.............. (i)

T₂-m₂g=m₂a..............(ii)

add (i) and................(ii)

m₁g-m₂g=m₁a+m₂a

g(m₁-m₂)=a(m₁+m₂)

10(2)=a(8)

20=8 a

20/8=a

a=2.5 m/s²

For finding T,

T-m₂g=m₂a

T-30=7.5

T=37.5N

Therefore Force on pulley by rope =2×Tension 

Force on pulley= 37.5N×2

Force=75N

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$\it\huge\mathfrak\red{Thanks}$]