Question

Two masses 50 kg and 100 kg are separated by a distance of 10 m. What is the gravitational force of attraction between them? G = 6.67 * 10^-11 Nm^2/kg^2​

Answer 1

Question:-

• Two masses 50 kg and 100 kg are separated by a distance of 10 m. What is the gravitational force of attraction between them?

Given Values:

• Two masses 50 kg and 100 kg are separated by a distance of 10 m.
• G = 6.67 * 10-¹¹ Nm²/kg²

To Find:

• What is the gravitational force of attraction between them.?

Solution:

$\sf \underline{ \purple{★According \: to \: the \: question : }}$

$\sf \blue➷ {m}^{1} = 50kg \: \: \: \: \: \: \: \: \: \\ \sf \blue➷ {m}^{2} = 100kg \: \: \: \: \: \: \: \\ \sf \blue➷distance = 10m$

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Now,Formula used :

$\tt{ \pink{\underline{\: ↬force = gravity \times {m}1 \times {m}2 \div {d}^{2} }}}$

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$\sf\underline{ \purple{❀ Now \:let's\:put \: up\: the \: values \: assigned \: which \: are \: given \: in \: the \: hint\: of \: the \: question}}$

$: \implies \bf{ 6.7 \times {10}^{ - 11} \times 50 \times \frac{100}{10} \times 10} \\ \\ : \implies \bf{67 \times {10}^{ - 12} \times \cancel \frac{5000}{100} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ : \implies \bf{ 67 \times \frac{10}{ - 12} \times 50} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ : \implies \bf 67 \times 5 \times 10 \times - 11 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ : \implies \sf 335 \times {10}^{ - 11} newton \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\pink{ \underline{ \boxed{ \purple{ \mathfrak{ \therefore \:force \: applied = 335 \times {10}^{ - 11} newton}}}}}\blue★$

◈━━━━━━━━━ ⸙ ━━━━━━━━━━ ◈

➺Info Related to force and pressure

$\pink➷ \rm \: force = mass \times acceleration \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \pink➷ \rm \: pressure = \frac{force}{acceleration} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \pink➷ \rm \: force \: on \: earth \: is \: 6 \: times \: more \: than \: force \: on \: moon$

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➺Do you know.?

$\sf\underline\blue{★newton's \:law \:of \:gravity}$

➷Newton's law of gravitation states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses.

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➷Additional info:

★The SI unit of pressure is pascal

★Hydrostatic Pressure Formula:

➺p equals density×gravity ×hieght

★ S.I unit of mass is kilogram

★gravity on earth= 9.81 m/s²

★Number of SI units are 7

★Momentum is measured as the product of Mass and velocity

★SI unit of mechanical power is watt

★SI unitof magnetic flux is Weber

★SI unit of mechanical power is watt

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hope this helps.!

#be brainly:)

Answer 2

${\large{\bold{\rm{\underline{Understanding \; the \; question}}}}}$

This question says that two masses of 50 kg and 100 kg are separated by a distance of 10 m. We have to find out that what is the gravitational force of attraction between them?

Hint is given for help that ${\sf{\red{G \: = \: 6.67 \times 10^{-11} \: Nm^{2} / kg^{2}}}}$

${\large{\bold{\rm{\underline{Given \; that}}}}}$

Mass m1 of a body = 50 kg.

Mass m2 of another body = 100 kg.

The two bodies are separated by a distance d of 10 metres.

${\large{\bold{\rm{\underline{To \; find}}}}}$

The gravitational force of attraction between them (2 bodies)

${\large{\bold{\rm{\underline{Solution}}}}}$

The gravitational force of attraction between them (2 bodies) = ${\sf{\red{335 \times 10^{-11}N}}}$

${\large{\bold{\rm{\underline{Full \; Solution}}}}}$

~ So according to the question, let's use given hint !

${\sf{\implies G \: = \: 6.67 \times 10^{-11} \: Nm^{2} / kg^{2}}}$

~ According to hint the coming equation is

${\sf{\implies F \: = \: G \times m1 \times m2 / d^{2}}}$

~ Let's substitute the values,

${\sf{\implies F \: = \: 6.7 \times 10^{-11} \times 50 \times 100/10 \times 10}}$

${\sf{\implies F \: = \: 6.7 \times 10^{-11} \times 5000/100}}$

${\sf{\implies F \: = \: 6.7 \times 10^{-11} \times 50}}$

${\sf{\implies F \: = \: 6.7 \times 50 \times 10^{-11}}}$

${\sf{\implies F \: = \: 335 \times 10^{-11}}}$

• Henceforth, the gravitational force of attraction between them (2 bodies) = ${\sf{\red{335 \times 10^{-11}N}}}$

${\large{\bold{\rm{\underline{Additional \; knowledge}}}}}$

Law of Gravitation :

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$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Maxwell \: is \: unit \: of \: magnetic \: flux}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: magnetic \: flux \: is \: Weber}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: surface \: tension \: is \: \dfrac{N}{m}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: mechanical \: power \: is \: Watt}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto 1 \: horsepower \: = \: approx \: 746 \: watts}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Momentum \: is \: measured \: as \: the \: product \: of \: Mass \: and \: velocity}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto \pi \: 'pi' \: is \: calculated \: by \: Aryabhatta}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto One \: J \: = \: 0.24 \: cal}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Kinetic \: energy \: is \: given \: by \: \dfrac{1}{2}mv^{2}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Value \: of \: G \: is \: 6.673 \times 10^{-11}Nm^{2}kg^{2}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Dimensional \: formula \: for \: universal \: gravitational \: constant \: is \: M^{-1} L^{3} T^{-2}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto The \: unit \: of \: force \: constant \: k \: of \: a \: spring \: is \: \dfrac{N}{m}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Sir \: Cavendish \: was \: the \: first \: to \: gave \: value \: of \: G \: experimentally}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto The \: Young's \: modulus \: for \: perfect \: rigid \: body \: is \: infinite}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Density \: is \: the \: ratio \: of \: \dfrac{Volume}{Mass}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Number \: of \: SI \: units \: are \: 7}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Ampere \: is \: the \: unit \: of \: current \: electricity}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: Young's \: modulus \: of \: elasticity \: is \: Newton/m^{2}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: pressure \: is \: Pascal}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Curie \: is \: the \: unit \: of \: radio \: activity}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Decibel \: is \: the \: unit \: of \: intensity \: of \: sound}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: electric \: charge \: is \: coulomb}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: resistance \: is \: ohm}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: acceleration \: is \: ms^{-2}}}}$