Question

Two masses 50 kg and 100 kg are separated by a distance of 10 m. What is the gravitational force of attraction between them? G = 6.67 * 10^-11 Nm^2/kg^2​

Answer 1

Answer:

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Explanation:

THE ANSWER IS IN THE PIC

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Answer 2

${ \underline{ \pmb{ \frak{Understanding \: the \: question : }}}}$

☀️Concept :Here it is said that, two masses of 50 kg and 100 kg are separated by a distance of 10 m. We have to find out that what is the gravitational force of attraction between them?

${ \underline{ \pmb{ \frak{Given \: values : }}}}$

★Mass (m₁) of the body is 50kg

★Mass (m₂) of the other body is 100kg

★Distance (d) between the bodies is 10m

${ \sf{ \red{hint :G = 6.67 \times {10}^{ - 11} \:{ {Nm}^{2} } / \: { {kg}^{2} } }}}$

${ \underline{ \pmb{ \frak{To \: find : }}}}$

★ The gravitational force acting between the 2 bodies of the given mass and distance

${ \underline{ \pmb{ \frak{ Using \: Concept: }}}}$

★The formula to find gravitational force according to the question is $\implies \sf F = G \times \dfrac{m_1 \times m_2}{ {d}^{2} }$

~we have to substitute the given value of G and the others accordingly

${ \underline{ \pmb{ \frak{ Solution: }}}}$

★The gravitational force acting between them is${ \sf{ \red{335 \times {10}^{ - 11} newton}}}$

${ \underline{ \pmb{ \frak{ Full \: solution: }}}}$

~ We know that :

$\implies \sf F = G \times \dfrac{m_1 \times m_2}{ {d}^{2} }$

~As We have got the value of G in the hint the the other values in the question let's substitute them

${ : \implies} \tt \: F = 6.7 \times {10}^{ - 11} \times \frac{100 \times 50}{ {10}^{2} } \\ \\ \\ { : \implies} \tt F = 6.7 \times {10}^{ - 11} \times \cancel\frac{5000}{100} \: \: \: \: \: \: \: \: \: \\ \\ \\ { : \implies} \tt F = 6.7 \times {10}^{ - 11} \times 50 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ { : \implies} \tt F = 6.7 \times 50 \times {10}^{ - 11} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\\ \\ \\ { : \implies}{ \underline{ \boxed{\tt{ F = 335 \times {10}^{ - 11} N}} \bigstar}} \: \: \: \: \: \: \: \: \: \: \: \:\: \: \: \:$

• Hence the gravitational force acting between them is 335 × 10^-11N

${ \underline{ \pmb{ \frak{More \: to \: know : }}}}$

Law of gravitation:

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Do you know?

★ Force - MA

★ Pressure = F/A

★S.I unit of gravity = Newtons Kg

★ Gravity on earth = 6 times more than that on moon