Question

Two masses 52 kg and 48 kg
are attached to the ends of a
string that passes over
frictionless pulley. Find the
tension in the string and
acceleration in the bodies when
both the masses are moving
vertically.
​

Answer 1

FINAL ANSWER:

a = 0.4 m/cm²

GIVEN:

M1 = 52 Kg

M2 = 48 Kg

g = 10 m/s

TO FIND:

Find the  tension in the string and  acceleration

FORMULA USED:

$a=\frac{m1 - m2}{m1 + m2} * g$

SOLUTION:

∴    $a=\frac{m1 - m2}{m1 + m2} * g$

     $a=\frac{52 - 48}{52 + 48}*10$

     $a=\frac{40}{100} * 10$

     a = 0.4 m/cm²