Physics, asked by upadhyayularama46, 11 months ago

two masses A and B measuring 3 kg and 4 kg are connected by a massless and inextensible string. if a force of 20 N is applied to 7 kg the tension in the string is

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Answered by Anonymous
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 \underline{ \boxed{ \bold{ \huge{ \purple{Answer}}}}} \\  \\  \star \rm \:  \red{Given} \\  \\  \implies \rm \: Two \: masses \: A \: and \: B \:  of \: mass \: 3 \: kg \: and \: 7 \: kg \\  \rm \: are \: connected \: by \: massless \: and  \: inextensible \\  \rm \: string.   \\   \\  \implies \rm \: A \: force \: of  \: 20\:N \: applied \: on \: 7 \: kg \: mass. \\  \\  \star \rm \:  \red{To \: Find} \\  \\  \implies \rm \: tension \: in \: string \\  \\  \star \rm \:  \red{Formula} \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \boxed{ \pink{ \rm{F \tiny{net}} = (m{ \tiny{1}} + m{ \tiny{2}})a}}\\  \\  \implies \rm \: net \: force \: on \: 7 \: kg \: mass \: block \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \boxed{ \rm{ \pink{F{ \tiny{7 \: kg}} = 7a = F{ \tiny{net}} - T}}} \\  \\  \star \rm \:  \red{Calculation} \\  \\  \implies \rm \: F{ \tiny{net}} = 20 = (7 + 3)a \\  \\  \implies  \:  \boxed{ \rm{a = 2 \:  \frac{m}{ {s}^{2} }}}  \\  \\  \implies \rm \: 7a = 20 - T \\  \\  \implies \rm \: T = 20 - 14 = 6 \: N \\  \\   \huge{\blue{ \star}} \:  \boxed{ \orange{ \huge{ \rm{T = 6 \: N}}}} \:  \huge{ \blue{ \star}}

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