Question

Two masses and M1 and M2 are attached to the end of a string which passes over a pulley attached to the top of an inclined plane. Angle of inclination of the plane is \Theta. Take g = 10 ms-2 . If M1 = 10 kg , M2 = 5 kg , \Theta = 30°. What is the acceleration of M2?

Answer 1

Answer:

M1=10kg g=10

M2=5kg

Theta=30-

A=?

A

$\frac{10kg }{5kg} \times 10 \times \cos(30)$

Answer 2

Answer:

acc.. of m2 = 0

Explanation:

t - m1 g sin theta = m1 * a

t = 50 - 10a

t - m2 g = m2 * a

t = 50 + 5a

equating t  ......

50 + 5a = 50 - 10a

a = 0