Question

Two masses are hanging from either side of a massless, frictionless pulley. The first mass is 5 kg and the second mass is 6 kg. Determine the acceleration of the system when the masses are released.

Answer 1

Answer:

Explanation:

Since 6kg is heavier than 4 kg so it will accelerate down while 4 kg will accelerate up So the equation of net force on 6kg is

given as

6 * 10 T 6a =

equation of net force on 4kg is given as T-4*10= 4a

now add the above two equations

6 * 10 - 4 * 10 = (6 + 4) * a

60 40 = 10α

a = 2m/s²

So 6 kg will accelerate downwards while 4 kg will accelerate upwards with acceleration 2 m/s^2

now in order to find the tension force

T 4 * 10 = 4 * 2

T = 48N

So the tension in the string is 48 N

=

3