Question

two masses m and 2 m approach each alone in part at right angle to each other after collision the stick together and move out at 2 m per second and we'll get the second degree to the original direction of the match and what were the initial speed of the two particles ​

Answer 1

Answer:

HERE'S YOUR ANSWER

Explanation:

We can break the Final momentum of the ball down into two components: x and y. Since they are Perpendicular, mass m will provide x-component while 2m provides y. Therefore the momentum of mass m is  3mvfcos(37∘)  where  vf=2m/s  

The momentum of Mass 2m is  3mvfsin(37∘)  

Divide by mass of each particle to get the velocities. Mass m will be 4.792 m/s while mass 2m will be 1.806 m/s.

This makes sense, since if you draw a line right bisecting their paths and look at the path of the combined mass, it is slightly under the line, showing there is a higher contribution from mass m than 2m to the final momentum of the system.

PLZ MARK ME BRAINLIEST