Question

two masses m and 2m are placed in a fixed horizontal circular smooth hollow tube of radius R as shown the mass m is moving with speed U and the mass 2 m is stationary after the first collision the time elapsed for next collision (coefficient of restitution= 1/ 2)

Answer 1

Explanation:

Question 3.

Give the steps you will use to separate the variables and then solve the equation:

(a) 3n – 2 = 46

(b) 5m + 7 = 17

(c) 20p3=40

(d) 3p10=6

Solution:

(a) 3n – 2 = 46

⇒ 3n- 2 + 2 = 46+ 2 (adding 2 to both sides)

⇒ 3n = 48

⇒ 3n + 3 = 48 ÷ 3