Question

Two masses M and M/2 are joined together by
means of light inextensible string passed over
a frictionless pulley as shown in figure. When
the bigger mass is released, the small one will
ascent with an acceleration of​

Answer 1

Answer :-

$a = \dfrac{g}{3}$

Given :-

Two blocks of mass M and M/2 are joined with frictionless pulley.

To find :-

Acceleration of block of mass M/2.

Solution:-

Since,

The pulley is friction less.

Tension force is equal for two blocks.

Let tension force be T.

• For block of mass M.

→$Mg - T = Ma$

→$T = Mg - Ma$

→$T = M( g -a) ----1)$

• For block of mass M/2.

→$T - \dfrac{M}{2}g = \dfrac{M}{2}a$

→$\dfrac{2T- Mg}{2}= \dfrac{Ma}{2}$

→$2T - Mg = Ma$

• Put the value of T.

→$2(Mg - Ma ) -Mg = Ma$

→$2 Mg - 2 Ma - Mg = Ma$

→$Mg = 3Ma$

→$a = \dfrac{g}{3}$

hence,

The acceleration of block of mass M/2 is $\dfrac{g}{3}$

Answer 2

Answer:

g/3 is the correct answer