Question

two masses m1=1kg and m2=2kg are connected by a light string and suspended by means of a weightless pulley as shown in figure.​

Answer 1

The ratio between the masses is 20/9.

Explanation:

m2 m2g- T = m2 a

T- m1g = m1a

Solving these equations we get, a= g/3

Distance travelled by each block

S = ut + (1/2)at^2 = 20/3 m

Applying centre of mass formula

(m2 x s – m1 x s)/(m2 + m1) = 20/9

Hence the ratio between the masses is 20/9.

Also learn more

A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse sudden stop is struck at one end of the string, the disturbance will reach the other end in... ?https://brainly.in/question/2523686

Answer 2

Answer:

Answer is the 20/9.....

Hope u can do it