Question

two masses M1 4kg and M2 6 kg are connected by means of a light string which passes over a light frictionless Pulley shown in figure calculate acceleration of a two masses and tension in the string take. g 10 metre per second

Answer 1

Given :-

$\bullet \: \: m_1 = 4 \: kg \: \\ \ m_2 = 6 \: kg$

It is a frictionless pulley. and acceleration due to gravity (g = 10 m/s²)

To find :-

Tension and acceleration

Explanation:-

Refer the attachment.

Let consider the 4-kg block is moving upwards with an acceleration "a" and Tension is T . and the 6-kg block is moving downwords with acceleration "a" and Tension is T. and weight of the blocks will be acting downwards.

So, By free body diagram, writing the equation .

$\red{T - 4g = 4a} - - 1$

$\red{6g - T = 6a} - - 2$

Adding equation 1 and 2

$\implies \: T - 4g + 6g - T = 4a + 6a$

$\implies \: 2g = \: 10a$

$\implies \: 2(10) = \: 10a$

$\implies \: \: a = 2 \: m/s {}^{2}$

Acceleration of the blocks are 2 m/s²

Substituting acceleration (a) value in equation 1

$\implies \: T - 4g = 4(2)$

$\implies \: T - 4(10) = 4(2)$

$\implies \: T - 40 = 8$

$\implies \: T = 48 \: N$

Tension acting on the string is 48N