Question

Two masses m1=5g and m2=4.8kg tied to a string are hanging over a light frictionless pulley. What is the acceleration of the masses left free to move ?(g = 9.8m/s²)​

Answer 1

Answer:

acceleration = 0.2 m/s²

Explanation:

(5 + 4.8) a = 5g - 4.8g

a = 0.2g ÷ 9.8

= 0.2 × 9.8 ÷ 9.8

= 0.2 m/s²

Answer 2

Explanation:

Both the body are attached to same string, therefore both have same acceleration

Equation for mass1:mg-T1=ma

substitute value:5×10-T1=5a

Equation for mass2:T1-4.8×10=4.8a

on addition both equations (1),(2) 5×10-T1=5a

T1- 4.8×10=4.8a

T1 cancelled,we get

by taking 10 and a common equation is

10(5-4.8) =a(9.8)

10(0.2)=a(9.8)

2=9.8a

2÷9.8=a

~0.2m/s2