Question

two masses M1=5kg and M2= 10kg are connected and the ends of an inextensible string passing over a frictionless pulley as shown. when the masses are released then the acceleration of the masses will be

Answer 1

the M2 will get down

Answer 2

Answer:

The masses are released then the acceleration of the masses will be $\bold{4.9 \mathrm{m} / \mathrm{s}^{2}}$

Solution:

According to the question, the masses are given as 5 kg and 10 kg connected in a system so the acceleration of the system is calculated as follows –

Given:

m1 = 5 kg  

m2 = 10 kg

Acceleration of the system will be given by

$\begin{array}{l}{a=\frac{m 2}{m 1+m 2} \times g} \\ {a=(10 / 5+15) \times 9.8} \\ {a=10 / 20 \times 9.8} \\ \bold{{a=4.9 m / s^{2}}}\end{array}$